Respuesta :

Leader
Simply plug in x= -2 in to y = 4^x, and solve for y.

[tex]y=4^{-2}\\\\y = \frac{1}{4^2}\\\\\boxed{\bf{y=\frac{1}{16}}}[/tex]

So, the point (-2, ¹/₁₆) lies on the graph of y = 4^x.

Your final answer is y = ¹/₁₆.

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