Respuesta :

choixongdong
m<CJG = 1/2(124 - 76)
m<CJG =1/2(48)
m<CJG = = 24

answer
m<CJG = 24
Banabanana
The angle formed by the intersection of tangent and secant outside the circle equals half the difference of the intercepted arcs.

[tex]m \angle CJG = \cfrac{arc \ CBG - arc \ DEG}{2}= \cfrac{124-76}{2}= 24^o[/tex]