Let:
x = Roger height
y = Shauna height
z = Jane height
[tex]\begin{gathered} x=55\frac{4}{5}=\frac{279}{5} \\ y=x-1\frac{1}{6}=x-\frac{7}{6}=\frac{279}{5}-\frac{7}{6}=\frac{1639}{30} \\ z=y-1\frac{1}{3}=y-\frac{4}{3}=\frac{1639}{30}-\frac{4}{3}=53\frac{3}{10}in=\frac{533}{10}in=53.3in \end{gathered}[/tex]