Answer:
f(6) = 320
Step-by-step explanation:
This is similar to Recurrence Relation;
First off, let's find f(2)
- f(2) = 2f(2-1) = 2f(1) = 2•10 = 20
Then find f(3) up to f(6)
- f(3) = 2f(3-1) = 2f(2) = 2•20 = 40
- f(4) = 2f(4-1) = 2f(3) = 2•40 = 80
- f(5) = 2f(5-1) = 2f(4) = 2•80 = 160
- f(6) = 2f(6-1) = 2f(5) = 2•160 = 320
Thus, f(6) is 320
