Respuesta :

Hi1315

Answer:

[tex]15\pi[/tex]

Step-by-step explanation:

[tex] \frac{ \theta}{360} \times 2\pi \: r \\ \frac{150}{360} \times 2 \times \pi \times 18 \\ \frac{5400\pi}{360} \\ = 15\pi[/tex]