Respuesta :

sreedevi102

Answer:

:)

Step-by-step explanation:

[tex]\frac{4x^2 - 1}{(x+4)(2x-1)} = \frac{(2x)^2 - (1)^2}{(x+4)(2x-1)}[/tex]

                 [tex]=\frac{(2x-1)(2x+1)}{(x+4)(2x-1)}\\\\=\frac{2x+1}{x+4}[/tex]

rihannarichmond5

Answer:

i don't know

Step-by-step explanation:

it is very hard

sorry !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

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