x=12, y=[tex]6\sqrt{2}[/tex]
This triangle is a special right triangle, a 45-45-90 triangle. In this format, the the hypotenuse will be [tex]x\sqrt{2}[/tex], while the side lengths would be x. With this in mind we can already figure out y is [tex]6\sqrt{2}[/tex]. The hypotenuse would be [tex](6\sqrt{2} )(\sqrt{2} )=12[/tex]
