Answer:
Remainder would be [tex]5x^2+21[/tex]
Step-by-step explanation:
Given,
Dividend = [tex]x^5+x^4+x^3+x^2+x[/tex]
Divisor = [tex]x^3-4x[/tex]
Using long division ( shown below ),
We get,
[tex]\frac{x^5+x^4+x^3+x^2+x}{x^3-4x}=x^2+x+5+\frac{5x^2+21}{x^3-4x}[/tex]
Therefore,
Remainder would be [tex]5x^2+21[/tex]
