Answer:
[tex]\large\boxed{(x+5)^2+y^2=64}[/tex]
Step-by-step explanation:
The standard form of an equation of a circle:
[tex](x-h)^2+(y-k)^2=r^2[/tex]
(h, k) - center
r - radius
We have the center (-5, 0) and the radius r = 8. Substitute:
[tex](x-(-5))^2+(y-0)^2=8^2\\\\(x+5)^2+y^2=64[/tex]
