The integers are 2 and 3
Since the integers are consecutive :
Let the integers be :
Smaller integer = x and
Larger integer = x+1
The sum of both = 3x - 1
Hence,
x + (x + 1) = 3x - 1
x + x + 1 = 3x - 1
2x + 1 = 3x - 1
2x - 3x = - 1 - 1
-x = - 2
x = 2
The smaller integer, x = 2
The larger integer x + 1 = 2 + 1 = 3
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