we are given
[tex] \frac{(4ab-8a^2+12ac)}{4a} [/tex]
we can see that
4a is in multiple in numerator
so, we can factor it out
[tex] \frac{4a(b-2a+3c)}{4a} [/tex]
now, we can cancel 4a
and we get
[tex] (b-2a+3c) [/tex].............Answer
