-3 = x^2 + 4x + 1
Add 3 to both sides.
0 = x^2 + 4x + 4
Switch sides.
x^2 + 4x + 4 = 0
For the quadratic formula, a = 1, b = 4, c = 4
discriminant = b^2 - 4ac = 4^2 - 4(1)(4) = 16 - 16 = 0
When the discriminant equals zero, there is a single real solution.
Answer: There is a single, real solution.
