Respuesta :

gmany
[tex]r^{27}-s^{30}=r^{9\cdor3}-s^{10\cdot3}=(r^9)^3-(s^{10})^3\\\\=(r^9-s^{10})[(r^9)^2+r^9s^{10}(s^{10})^2]=(r^9-s^{10})(r^{18}+r^9s^{10}+s^{20})\\\\Used:\\\\(a^n)^m=a^{n\cdot m}\\\\a^3-b^3=(a-b)(a^2+ab+b^2)[/tex]
aaronvenugopal24

Answer:

(r^9 - s^10) (r^18 + r^9 s^10 + s^20)Step-by-step explanation: